84.01g of NaHCO3g react with 36.46g of HCl to produce 58.44g of NaCl. Calculate the percentage yield of NaCl?

First, we need to calculate the theoretical yield of NaCl using the given information:

1. Calculate the molar mass of NaHCO3:
Na = 22.99 g/mol
H = 1.01 g/mol
C = 12.01 g/mol
O = 16.00 g/mol
NaHCO3 = 22.99 + 1.01 + 12.01 + (3 * 16.00) = 84.01 g/mol

2. Calculate the moles of NaHCO3:
moles = mass / molar mass
moles = 84.01g / 84.01 g/mol = 1 mol

3. Use the balanced chemical equation to determine the moles of NaCl produced:
NaHCO3 + HCl -> NaCl + H2O + CO2
1 mol NaHCO3 produces 1 mol NaCl

4. Calculate the molar mass of NaCl:
Na = 22.99 g/mol
Cl = 35.45 g/mol
NaCl = 22.99 + 35.45 = 58.44 g/mol

5. Calculate the theoretical yield of NaCl:
theoretical yield = moles of NaCl * molar mass of NaCl
theoretical yield = 1 mol * 58.44 g/mol = 58.44 g

Now, we can calculate the percentage yield of NaCl:

Percentage yield = (actual yield / theoretical yield) * 100
Percentage yield = (58.44g / 58.44g) * 100
Percentage yield = 100%

Therefore, the percentage yield of NaCl is 100%.

Step 1: Calculate the theoretical yield of NaCl

Balanced chemical equation:

NaHCO3 + HCl → NaCl + H2O + CO2

Moles of NaHCO3 = 84.01 g / 84.01 g/mol = 1 mol
Moles of HCl = 36.46 g / 36.46 g/mol = 1 mol

From the balanced equation, we see that 1 mole of NaHCO3 reacts with 1 mole of HCl to produce 1 mole of NaCl. Therefore, the theoretical yield of NaCl is also 1 mole.

Mass of theoretical yield of NaCl = 1 mol - 58.44 g/mol = 58.44 g

Step 2: Calculate the percentage yield

Percentage yield = (Actual yield / Theoretical yield) x 100%

Actual yield = 58.44 g
Theoretical yield = 58.44 g

Percentage yield = (58.44 g / 58.44 g) x 100% = 100%

Therefore, the percentage yield of NaCl is 100%.