84.01g of NaHCO3 react with 36.46g of HCl to produce 58.44g of NaCl. Calculate the theoretical yield of NaCl?

To calculate the theoretical yield of NaCl, we first need to determine the limiting reactant in the reaction.

1. Calculate the molar mass of NaHCO3:
Na = 22.99 g/mol
H = 1.01 g/mol
C = 12.01 g/mol
O = 16.00 g/mol
NaHCO3 = 22.99 + 1.01 + 12.01 + (3 * 16.00) = 84.01 g/mol

2. Calculate the number of moles of NaHCO3:
84.01g NaHCO3 / 84.01 g/mol = 1 mol NaHCO3

3. Calculate the number of moles of HCl:
36.46g HCl / 36.46 g/mol = 1 mol HCl

4. Determine the limiting reactant:
Since both reactants have the same number of moles, NaHCO3 is the limiting reactant.

5. Calculate the theoretical yield of NaCl:
From the balanced chemical equation:
NaHCO3 + HCl -> NaCl + H2O + CO2

The molar mass of NaCl is 58.44 g/mol.

1 mol NaCl = 58.44 g NaCl
1 mol NaHCO3 produces 1 mol NaCl

1 mol NaHCO3 = 58.44 g NaCl
1 mol NaHCO3 = 58.44 g NaCl

1 mol NaHCO3 = 58.44 g NaCl
1 mol NaHCO3 = 58.44 g NaCl

Therefore, the theoretical yield of NaCl is 58.44g.

Balanced chemical equation:

```
NaHCO3 + HCl → NaCl + H2O + CO2
```

Moles of reactants:

Moles of NaHCO3 = 84.01 g / 84.01 g/mol = 1 mol
Moles of HCl = 36.46 g / 36.46 g/mol = 1 mol

Mole ratio:

From the balanced equation, the mole ratio of NaHCO3 to NaCl is 1:1.

Theoretical yield of NaCl:

Theoretical yield = Moles of NaHCO3 × Molar mass of NaCl
Theoretical yield = 1 mol × 58.44 g/mol
Theoretical yield = 58.44 g

Therefore, the theoretical yield of NaCl is 58.44 g.