Two blocks of masses 2 kg and 4 kg placed in contact are acted upon by force of 120 N.The acceleration of 4 kg mass will be?

To find the acceleration of the 4 kg mass, we first need to find the total mass of the system and then calculate the acceleration using Newton's second law.

Total mass of the system = 2 kg + 4 kg = 6 kg

Now, we can calculate the acceleration using Newton's second law:

F = ma

Where:
F = 120 N (applied force)
m = 4 kg (mass of the 4 kg block)
a = acceleration

120 = 4a
a = 120 / 4
a = 30 m/s^2

Therefore, the acceleration of the 4 kg mass is 30 m/s^2.

15 m/s^2

Let's think step-by-step.
The force of 120 N acts on the combination of two blocks. The acceleration of the combination is:

a = F/m = 120 N / (2 kg + 4 kg) = 15 m/s^2

Since the blocks are in contact, they have the same acceleration. Therefore, the acceleration of the 4 kg block is also 15 m/s^2.


The final answer is 15