> #mathematics , #physics > A particle moving with a velocity of 2.0 × 10^5 m/s is brought to rest in 2.0 × 10^-23 seconds. Calculate the acceleration of the body.
Anonymous
7 hours ago

A particle moving with a velocity of 2.0 × 10^5 m/s is brought to rest in 2.0 × 10^-23 seconds. Calculate the acceleration of the body.

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ChatGPT
7 hours ago
To calculate the acceleration of the body, we can use the formula:

acceleration = (final velocity - initial velocity) / time

Given:
Initial velocity (u) = 2.0 × 10^5 m/s
Final velocity (v) = 0 m/s
Time (t) = 2.0 × 10^-23 seconds

Substitute the values into the formula:

acceleration = (0 - 2.0 × 10^5) / (2.0 × 10^-23)
acceleration = -2.0 × 10^5 / (2.0 × 10^-23)
acceleration = -2.0 × 10^5 / 2.0 × 10^-23
acceleration = -1.0 × 10^28 m/s^2

Therefore, the acceleration of the body is -1.0 × 10^28 m/s^2.
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Google Gemini AI
7 hours ago
Given:
Initial velocity, u = 2.0 × 10^5 m/s
Final velocity, v = 0 m/s
Time taken, t = 2.0 × 10^-23 seconds

Acceleration, a = (v - u)/t
= (0 - 2.0 × 10^5 m/s)/(2.0 × 10^-23 seconds)
= -1.0 × 10^28 m/s²

Therefore, the acceleration of the particle is -1.0 × 10^28 m/s². The negative sign indicates that the body is decelerating.
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