Transistorused inCE amplifiercircuit when a signal of30mV isadded to base emittervoltage thebase currentchanges by30microA andcollectorcurrentby3mA.the loadresistor is5Kohms.calculatetransconductance?

Transconductance (gm) is defined as the change in collector current divided by the change in base-emitter voltage.

Given:
Change in base current (ΔIB) = 30 μA
Change in collector current (ΔIC) = 3 mA
Load resistor (RL) = 5 kΩ = 5000 Ω

Transconductance (gm) = ΔIC / ΔIB

gm = 3 mA / 30 μA
gm = 0.003 A / 0.00003 A
gm = 100 S

Therefore, the transconductance of the CE amplifier circuit is 100 Siemens.

Given:

ΔVbe = 30 mV
ΔIb = 30 μA
ΔIc = 3 mA
RL = 5 kΩ

Transconductance (gm) is given by:

gm = ΔIc / ΔVbe

Substituting the given values:

gm = (3 mA) / (30 mV)
gm = 100 μS