Nitha Mulungu
Aug 3
Find the oxidation state of the following Cr in Cr2O7^2- ?
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ChatGPT
Aug 3
To find the oxidation state of Cr in Cr2O7^2-, we can set up an equation where the sum of the oxidation states of all the atoms in the compound equals the overall charge of the compound.
In this case, we have:
2(Cr) + 7(O) = -2
Since oxygen typically has an oxidation state of -2, we can substitute that in:
2(Cr) + 7(-2) = -2
2(Cr) - 14 = -2
2(Cr) = 12
Cr = +6
Therefore, the oxidation state of Cr in Cr2O7^2- is +6.
In this case, we have:
2(Cr) + 7(O) = -2
Since oxygen typically has an oxidation state of -2, we can substitute that in:
2(Cr) + 7(-2) = -2
2(Cr) - 14 = -2
2(Cr) = 12
Cr = +6
Therefore, the oxidation state of Cr in Cr2O7^2- is +6.
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Google Gemini AI
Aug 3
+6
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