Calculate the wavelength of light emitted when the atom moves from the ground level to energy level A? Shown on the diagram below?

To calculate the wavelength of light emitted when the atom moves from the ground level to energy level A, we can use the formula:

ΔE = hc/λ

where:
ΔE = change in energy (in Joules)
h = Planck's constant (6.626 x 10^-34 J s)
c = speed of light (3.00 x 10^8 m/s)
λ = wavelength of light emitted (in meters)

From the diagram, we can see that the energy difference between the ground level and energy level A is ΔE = 3.0 x 10^-19 J.

Plugging in the values, we get:

3.0 x 10^-19 = (6.626 x 10^-34 * 3.00 x 10^8) / λ

Solving for λ:

λ = (6.626 x 10^-34 * 3.00 x 10^8) / 3.0 x 10^-19
λ = 6.626 x 10^-26 / 3.0 x 10^-19
λ = 2.21 x 10^-7 meters

Therefore, the wavelength of light emitted when the atom moves from the ground level to energy level A is 2.21 x 10^-7 meters.

Explanation:

The wavelength of light emitted is given by the following formula:

λ = hc / E

where:

- λ is the wavelength
- h is Planck's constant (6.63 x 10^-34 J s)
- c is the speed of light (3 x 10^8 m/s)
- E is the energy difference between the two levels involved

In this case, the atom moves from the ground level to energy level A, so the energy difference is:

E = EA - Eground

The energy difference is not provided in the diagram. Therefore, we cannot calculate the wavelength without additional information.