Calculate the pressure at the bottom of a swimming pool that is 100 cm deep, assuming an acceleration due to gravity of 10 m/s² and a water density of 1000 kg/m³.

To calculate the pressure at the bottom of the swimming pool, we can use the formula for pressure:

Pressure = density x gravity x height

Given:
Density of water (ρ) = 1000 kg/m³
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 100 cm = 1 m

Plugging in the values:

Pressure = 1000 kg/m³ x 10 m/s² x 1 m
Pressure = 10000 N/m²

Therefore, the pressure at the bottom of the swimming pool is 10000 N/m² or 10000 Pa.

The pressure at the bottom of the swimming pool is given by the formula:

$$P = \rho g h$$

where:

- P is the pressure in pascals (Pa)
- ρ is the density of the water in kilograms per cubic meter (kg/m³)
- g is the acceleration due to gravity in meters per second squared (m/s²)
- h is the depth of the water in meters (m)

In this case, we have:

- ρ = 1000 kg/m³
- g = 10 m/s²
- h = 100 cm = 1 m

So, the pressure at the bottom of the swimming pool is:

$$P = 1000 kg/m³ - 10 m/s² - 1 m = 10,000 Pa$$

Therefore, the pressure at the bottom of the swimming pool is 10,000 Pa.