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Dec 11, 2023
To solve the equation X = log2(0.125), we need to rewrite 0.125 as a power of 2.
0.125 can be written as 1/8, which is equal to 2^(-3).
Therefore, X = log2(2^(-3)).
Using the logarithmic property logb(b^x) = x, we can simplify the equation to:
X = -3.
So, X = -3.
0.125 can be written as 1/8, which is equal to 2^(-3).
Therefore, X = log2(2^(-3)).
Using the logarithmic property logb(b^x) = x, we can simplify the equation to:
X = -3.
So, X = -3.
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