In the years, Joel's father will be six times as old as Joel was last year. When Joel's age is added to his father's present age, the total is 68. How old is each one now?

Let's represent Joel's current age as J and his father's current age as F.

According to the first statement, in x years, Joel's father will be six times as old as Joel was last year. This can be represented as:

F + x = 6(J - 1)

According to the second statement, when Joel's age is added to his father's present age, the total is 68. This can be represented as:

J + F = 68

We can now solve these two equations simultaneously to find the values of J and F.

From the first equation, we can express x in terms of J and F:

x = 6(J - 1) - F

Substitute this expression for x into the second equation:

6(J - 1) - F + J + F = 68
6J - 6 - F + J + F = 68
7J - 6 = 68
7J = 74
J = 10.57 (approx.)

Now, substitute J back into the second equation to find F:

10.57 + F = 68
F = 57.43 (approx.)

Therefore, Joel is approximately 11 years old and his father is approximately 57 years old.

Let's assume that Joel's age now is x and his father's age now is y.

From the given information, we can create two equations:

1) y + 6 = 6(x - 1)
2) x + y = 68

Let's simplify the first equation:
y + 6 = 6x - 6
y = 6x - 12

Now, substitute this expression for y into the second equation:
x + (6x - 12) = 68
7x = 80
x = 11.43 (approximately)

Since Joel's age must be a whole number, let's assume it's 11.

Now, substitute x = 11 back into the equation y = 6x - 12:
y = 6(11) - 12
y = 57

Therefore, Joel's age now is 11 and his father's age now is 57.