When a fruit vendor arranged her fruit in groups of 3,4and 5,she has 2 fruit remaining.whatcould be the minimum number of fruit in her bag?

The minimum number of fruit in her bag would be the least common multiple of 3, 4, and 5 plus 2.

The least common multiple of 3, 4, and 5 is 60.

Therefore, the minimum number of fruit in her bag would be 60 + 2 = 62.

Let the minimum number of fruits be x
Then
x - 2 = 3m = 4n = 50
x - 2 = LCM (3,4,5) - some integer
x -2 = 60 - some integer
minimum value of x=60

Therefore,minimum number of fruits is 62