A person holds an 80 N weight 2 m above the floor for 30 seconds. What is the power required to do this?

To calculate the power required to hold the weight 2 m above the floor for 30 seconds, we first need to calculate the work done in lifting the weight.

Work = Force x Distance
Work = 80 N x 2 m
Work = 160 J

Next, we need to calculate the power using the formula:

Power = Work / Time
Power = 160 J / 30 s
Power = 5.33 watts

Therefore, the power required to hold the weight 2 m above the floor for 30 seconds is 5.33 watts.

Power is the rate at which work is done. Work is the force applied to an object multiplied by the distance the object moves in the direction of the force. In this case, the force is the weight of the object, which is 80 N, and the distance is the height the object is lifted, which is 2 m. Therefore, the work done is:

$$W = Fd = (80 N)(2 m) = 160 J$$

The time it takes to do the work is 30 seconds. Therefore, the power required is:

$$P = \frac{W}{t} = \frac{160 J}{30 s} = 5.33 W$$

Therefore, the power required is 5.33 W.