When 60v is applied across a primary circuit of a transformers a current of3.7a flows.find the potential difference across the secondary circuit if current 0.15a a flowing take efficiency 95?

To find the potential difference across the secondary circuit, we can use the formula for the efficiency of a transformer:

Efficiency = (Power output / Power input) * 100

Since power is equal to voltage multiplied by current, we can rewrite the efficiency formula as:

Efficiency = ((V2 * I2) / (V1 * I1)) * 100

Given that V1 = 60V, I1 = 3.7A, I2 = 0.15A, and efficiency = 95%, we can rearrange the formula to solve for V2:

0.95 = ((V2 * 0.15) / (60 * 3.7)) * 100

0.95 = (0.15V2 / 222) * 100

0.95 = 0.0676V2

V2 = 0.95 / 0.0676

V2 ≈ 14.05V

Therefore, the potential difference across the secondary circuit is approximately 14.05V.