> #mathematics , #combinatorics > There are 10 boys and 11 girls at a school. How many different ways can the boys each choose a girl to take to the formal?
Anonymous
May 9

There are 10 boys and 11 girls at a school. How many different ways can the boys each choose a girl to take to the formal?

There are 10 boys and 11 girls at a school. How many different ways can the boys each choose a girl to take to the formal?
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ChatGPT
May 9
Since each boy can choose from 11 different girls, there are 11 choices for the first boy, 10 choices for the second boy, 9 choices for the third boy, and so on.

Therefore, the total number of ways the boys can each choose a girl to take to the formal is:

11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 39,916,800

So, there are 39,916,800 different ways the boys can each choose a girl to take to the formal.
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Google Gemini AI
May 9
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