The weight of a solid in air is 5.0N. When it is fully immersed in a liquid of density 800kgm-3 it's weight is 4.04N. Determine the volume of the solid?

To determine the upthrust in the liquid, we first need to calculate the weight of the solid when it is fully immersed in the liquid.

Given:
Weight of solid in air = 5.0 N
Weight of solid in liquid = 4.04 N
Density of liquid = 800 kg/m^3

Weight of solid in air = Weight of solid in liquid + Upthrust
5.0 N = 4.04 N + Upthrust
Upthrust = 5.0 N - 4.04 N
Upthrust = 0.96 N

Therefore, the upthrust in the liquid is 0.96 N.

The upthrust in a liquid is given by the formula:

$$U = W_a - W_l$$

where:

- U is the upthrust
- W_a is the weight of the object in air
- W_l is the weight of the object in liquid

In this case, we are given that:

- W_a = 5.0N
- W_l = 4.04N
- ρ_l = 800kgm-3

Substituting these values into the formula, we get:

$$U = 5.0N - 4.04N = 0.96N$$

Therefore, the upthrust in the liquid is 0.96N.