The solution set of the equation [2x+1]=10 is A)[9/5,2) B)[9/2,5] C)(-infinity,9/2] D)(-infinity, 9/2] union (5, infinity)?

To solve the equation [2x+1]=10, we need to consider two cases: when 2x+1 is positive and when it is negative.

Case 1: 2x+1 is positive
When 2x+1 is positive, the equation becomes 2x+1=10. Solving for x, we have:
2x+1=10
2x=9
x=9/2

Case 2: 2x+1 is negative
When 2x+1 is negative, the equation becomes -(2x+1)=10. Solving for x, we have:
-(2x+1)=10
-2x-1=10
-2x=11
x=-11/2

Therefore, the solution set of the equation [2x+1]=10 is x in the interval (-infinity, -11/2] union [9/2, infinity).
The answer is D) (-infinity, 9/2] union (5, infinity).