Find the sum of the four-digit number formed from 2, 5, 3, 8 if each digit is used once in each arrangement.

To find the sum of all possible four-digit numbers formed from 2, 5, 3, 8, we need to consider all permutations of these digits.

The four-digit numbers that can be formed are:
2538, 2583, 2358, 2385, 2853, 2835,
5238, 5283, 5328, 5382, 5823, 5832,
3258, 3285, 3528, 3582, 3825, 3852,
8253, 8235, 8523, 8532, 8325, 8352,
5238, 5283, 5328, 5382, 5823, 5832,
8253, 8235, 8523, 8532, 8325, 8352.

Adding all these numbers together, we get:
2538 + 2583 + 2358 + 2385 + 2853 + 2835 + 5238 + 5283 + 5328 + 5382 + 5823 + 5832 + 3258 + 3285 + 3528 + 3582 + 3825 + 3852 + 8253 + 8235 + 8523 + 8532 + 8325 + 8352 = 100,800.

Therefore, the sum of all possible four-digit numbers formed from 2, 5, 3, 8 is 100,800.

The sum of the four-digit number formed from 2, 5, 3, 8 if each digit is used once in each arrangement is:
$$2538 + 2583 + 2853 + 2835 + 3258 + 3285 + 3528 + 3582 + 5238 + 5283 + 5328 + 5382 + 8253 + 8352 + 8235 + 8325 = 44556$$