Suppose a 0.2kg baseball is traveling at 40m/s.After being hit by the bat,the ball,s velocity is 50cm/s in opposite direction.Find the impluse?

To find the impulse, we can use the formula:

Impulse = change in momentum

First, we need to calculate the initial momentum of the baseball:

Initial momentum = mass x initial velocity
Initial momentum = 0.2kg x 40m/s
Initial momentum = 8 kg*m/s

Next, we calculate the final momentum of the baseball:

Final momentum = mass x final velocity
Final momentum = 0.2kg x (-50m/s) [since the final velocity is in the opposite direction]
Final momentum = -10 kg*m/s

Now, we can calculate the change in momentum:

Change in momentum = Final momentum - Initial momentum
Change in momentum = -10 kg*m/s - 8 kg*m/s
Change in momentum = -18 kg*m/s

Therefore, the impulse experienced by the baseball is 18 kg*m/s in the direction opposite to its initial motion.

Initial momentum (before the hit):

p_i = m - v_i = 0.2 kg - 40 m/s = 8 kg m/s

Final momentum (after the hit):

p_f = m - v_f = 0.2 kg - (-0.5 m/s) = -0.1 kg m/s

Impulse (change in momentum):

Impulse = p_f - p_i = -0.1 kg m/s - 8 kg m/s = -8.1 kg m/s

Therefore, the impulse exerted on the baseball is -8.1 kg m/s. The negative sign indicates that the impulse is in the opposite direction of the initial momentum, which is towards the pitcher.