1000 tickets were sold for Century Cinemax. Adult tickets cost TZS 8500, and children's tickets cost TZS 4500. A total of 7300 was collected. How many tickets of each kind were sold?

Let x be the number of adult tickets sold and y be the number of children's tickets sold.

From the information given, we can create the following system of equations:

x + y = 1000 (equation 1)
8500x + 4500y = 7300 (equation 2)

To solve this system of equations, we can first solve equation 1 for x:

x = 1000 - y

Substitute this expression for x into equation 2:

8500(1000 - y) + 4500y = 7300
8500000 - 8500y + 4500y = 7300
4000y = 1197000
y = 297.5

Since we cannot have a fraction of a ticket, this means that there was an error in the information given. Please check the values provided.

Let the number of adult tickets sold be x and the number of children's tickets sold be y.

Then, x + y = 1000 (Total tickets sold)

8500x + 4500y = 7300000 (Total money collected)

Solving these equations:

y = 1000 - x

8500x + 4500(1000 - x) = 7300000

4000x = 2800000

x = 700

Therefore, the number of adult tickets sold is 700 and the number of children's tickets sold is 1000 - 700 = 300.