Edward Yayi
May 10
Solve the triangle 📐 x72 in which y =9 and z= 6.5 and <y×2=72°?
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ChatGPT
May 10
To solve this triangle, we need to find the missing side and angles.
Given:
y = 9
z = 6.5
First, we can find the missing angle by dividing 72° by 2:
Now, we can use the Law of Sines to find the missing side x:
sin(x) / x = sin(y) / y
sin(x) / x = sin(36°) / 9
sin(x) = (x * sin(36°)) / 9
sin(x) = (x * 0.5878) / 9
sin(x) = 0.0653x
Now, we can use the Law of Sines to find the missing side x:
sin(x) / x = sin(z) / z
sin(x) / x = sin(6.5) / 6.5
sin(x) = (x * sin(6.5)) / 6.5
sin(x) = (x * 0.1132) / 6.5
sin(x) = 0.0174x
Now, we can set the two expressions for sin(x) equal to each other:
0.0653x = 0.0174x
0.0653x - 0.0174x = 0
0.0479x = 0
x = 0 / 0.0479
x = 0
Therefore, the triangle is not possible to solve with the given information.
Given:
y = 9
z = 6.5
First, we can find the missing angle by dividing 72° by 2:
Now, we can use the Law of Sines to find the missing side x:
sin(x) / x = sin(y) / y
sin(x) / x = sin(36°) / 9
sin(x) = (x * sin(36°)) / 9
sin(x) = (x * 0.5878) / 9
sin(x) = 0.0653x
Now, we can use the Law of Sines to find the missing side x:
sin(x) / x = sin(z) / z
sin(x) / x = sin(6.5) / 6.5
sin(x) = (x * sin(6.5)) / 6.5
sin(x) = (x * 0.1132) / 6.5
sin(x) = 0.0174x
Now, we can set the two expressions for sin(x) equal to each other:
0.0653x = 0.0174x
0.0653x - 0.0174x = 0
0.0479x = 0
x = 0 / 0.0479
x = 0
Therefore, the triangle is not possible to solve with the given information.
0
Google Gemini AI
May 10
Given data:
In triangle △x72,
y = 9
z = 6.5
To find:
x
Using the sine rule, we have:
x/sin x = y/sin y = z/sin z
Since
We don't have the value of
Since the sum of the interior angles of a triangle is 180°, we have:
Substituting the given value of
Since
180° -
-
-108° <
Therefore, the possible range of values for
In triangle △x72,
y = 9
z = 6.5
To find:
x
Using the sine rule, we have:
x/sin x = y/sin y = z/sin z
Since
We don't have the value of
Since the sum of the interior angles of a triangle is 180°, we have:
Substituting the given value of
Since
180° -
-
-108° <
Therefore, the possible range of values for
0
