Rapa buys 3 apples and 2 pears at a fruit stall and is charged K4.20. Rani buys 4 apple and 3 pears and is charged K5.20 .How much does each apple and pear cost?

Let the cost of each apple be A and the cost of each pear be P.

From the given information, we can set up the following equations:

3A + 2P = 4.20
4A + 3P = 5.20

To solve these equations, we can use the method of substitution or elimination. Let's use the method of substitution:

From the first equation, we can express A in terms of P:
A = (4.20 - 2P) / 3

Substitute this expression for A into the second equation:
4((4.20 - 2P) / 3) + 3P = 5.20
(16.80 - 8P) / 3 + 3P = 5.20
16.80 - 8P + 9P = 15.60
P = 0.60

Now, substitute the value of P back into the first equation to find the value of A:
3A + 2(0.60) = 4.20
3A + 1.20 = 4.20
3A = 3.00
A = 1.00

Therefore, each apple costs K1.00 and each pear costs K0.60.