Okello has a son and two daughters. Ann is \( k \) years old, and he is three times as old as Ann. Cissy is twice as old as James. The product of the ages of the two daughters is 24. How old is James?

Let's break down the information given:

1. Ann is \( k \) years old, and Okello is three times as old as Ann. So, Okello is \( 3k \) years old.
2. Cissy is twice as old as James. Let's denote James' age as \( j \). So, Cissy is \( 2j \) years old.
3. The product of the ages of the two daughters is 24. This means that \( k \times j = 24 \).

From the information given, we can form the following equations:

1. \( 3k = \text{Okello's age} \)
2. \( 2j = \text{Cissy's age} \)
3. \( k \times j = 24 \)

Since Cissy is twice as old as James, we can substitute \( 2j \) for Cissy's age in the product equation:

\( k \times 2j = 24 \)
\( 2kj = 24 \)
\( kj = 12 \)

Now, we can substitute \( kj = 12 \) into the equation for Okello's age:

\( 3k = 3 \times k = 3 \times \frac{12}{j} = 36 \)

Therefore, Okello is 36 years old. Since Cissy is twice as old as James, and the product of their ages is 24, James must be 3 years old.

Step 1: Assign Variables

- Let \( J \) be James' age.
- Let \( C \) be Cissy's age.
- Let \( A \) be Ann's age.

Step 2: Translate the Given Information into Equations

- Okello is three times as old as Ann: \( A = J / 3 \).
- Cissy is twice as old as James: \( C = 2J \).
- Product of the daughters' ages is 24: \( A \times C = 24 \).

Step 3: Solve the Equations

Substitute the first equation into the third equation:

$$ \frac{J}{3} \times 2J = 24 $$

$$ 2J^2 = 24 $$

$$ J^2 = 12 $$

$$ J = \sqrt{12} = 2\sqrt{3} $$

Therefore, James is \( 2\sqrt{3} \) years old.