Let A=(aij)2×3 and aij=j-i then determine A ?

To determine A, we need to find the values of each element aij.

Given that aij = j - i, we can substitute the values of i and j to find the corresponding elements.

For i = 1 and j = 1:
a11 = 1 - 1 = 0

For i = 1 and j = 2:
a12 = 2 - 1 = 1

For i = 1 and j = 3:
a13 = 3 - 1 = 2

For i = 2 and j = 1:
a21 = 1 - 2 = -1

For i = 2 and j = 2:
a22 = 2 - 2 = 0

For i = 2 and j = 3:
a23 = 3 - 2 = 1

Therefore, A =
| 0 1 2 |
| -1 0 1 |