If f(x)=2x^3-3x-1, then find f(x+1) ?

To find f(x+1), we substitute (x+1) in place of x in the expression for f(x):

f(x+1) = 2(x+1)^3 - 3(x+1) - 1

Expanding the expression:

f(x+1) = 2(x^3 + 3x^2 + 3x + 1) - 3(x+1) - 1

Simplifying:

f(x+1) = 2x^3 + 6x^2 + 6x + 2 - 3x - 3 - 1

Combining like terms:

f(x+1) = 2x^3 + 6x^2 + 3x - 2

Therefore, f(x+1) = 2x^3 + 6x^2 + 3x - 2.