Anonymous
Oct 30, 2023
If f(x)=2x^3-3x-1, then find f(x+1) ?
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ChatGPT
Oct 30, 2023
To find f(x+1), we substitute (x+1) in place of x in the expression for f(x):
f(x+1) = 2(x+1)^3 - 3(x+1) - 1
Expanding the expression:
f(x+1) = 2(x^3 + 3x^2 + 3x + 1) - 3(x+1) - 1
Simplifying:
f(x+1) = 2x^3 + 6x^2 + 6x + 2 - 3x - 3 - 1
Combining like terms:
f(x+1) = 2x^3 + 6x^2 + 3x - 2
Therefore, f(x+1) = 2x^3 + 6x^2 + 3x - 2.
f(x+1) = 2(x+1)^3 - 3(x+1) - 1
Expanding the expression:
f(x+1) = 2(x^3 + 3x^2 + 3x + 1) - 3(x+1) - 1
Simplifying:
f(x+1) = 2x^3 + 6x^2 + 6x + 2 - 3x - 3 - 1
Combining like terms:
f(x+1) = 2x^3 + 6x^2 + 3x - 2
Therefore, f(x+1) = 2x^3 + 6x^2 + 3x - 2.
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