If 9531A2 is divisible by 3, then what is the possible maximum value of A?

To determine if 9531A2 is divisible by 3, we need to find the sum of its digits and see if that sum is divisible by 3.

9 + 5 + 3 + 1 + A + 2 = 20 + A

For 9531A2 to be divisible by 3, the sum of its digits must be divisible by 3. Therefore, 20 + A must be divisible by 3.

The possible values of A that make 20 + A divisible by 3 are 1, 4, and 7.

Therefore, the possible maximum value of A is 7.

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