height of h metres of a cricket ball after being struck by batsman is by the equation h=1+x-(x^2/40)wherex metres is horizontal distance traveled by ball from bat.How far ball travel before landing?

To find the horizontal distance the ball travels before landing, we need to find the value of x when h = 0 (i.e. when the height of the ball is 0).

Given the equation h = 1 + x - (x^2/40), we can set h = 0 and solve for x:

0 = 1 + x - (x^2/40)
x^2/40 - x - 1 = 0

Now, we can solve this quadratic equation for x using the quadratic formula:

x = (-(-1) ± sqrt((-1)^2 - 4*(1)*(-1)))/(2*(1))
x = (1 ± sqrt(1 + 4))/2
x = (1 ± sqrt(5))/2

Therefore, the horizontal distance the ball travels before landing is x = (1 + sqrt(5))/2 or x = (1 - sqrt(5))/2.

Step 1: Set h = 0 to find the landing point.

When the ball lands, it hits the ground, so h = 0:

```
0 = 1 x - (x^2/40)
```

Step 2: Solve the quadratic equation.

Rearrange the equation:

```
x^2/40 = 1 x
```

Multiply both sides by 40:

```
x^2 = 40 x
```

Factor out an x:

```
x(x - 40) = 0
```

Solve for x:

```
x = 0 or x = 40
```

Step 3: Discard the trivial solution.

x = 0 represents the height of the ball, not the horizontal distance traveled. So we discard this solution.

Step 4: The ball travels 40 meters before landing.

Therefore, the horizontal distance traveled by the ball before landing is:

```
x = 40 meters
```