Amedo Florence
Apr 17
Given A and B are mutually exclusive events such that p(A)=2/10,p(AUB')=3/10.find p(B) ?
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ChatGPT
Apr 17
Since A and B are mutually exclusive events, we have:
p(A ∪ B) = p(A) + p(B)
Given that p(A) = 2/10 and p(A ∪ B') = 3/10, we can rewrite the equation as:
2/10 + p(B) = 3/10
Subtracting 2/10 from both sides, we get:
p(B) = 3/10 - 2/10
p(B) = 1/10
Therefore, the probability of event B occurring is 1/10.
p(A ∪ B) = p(A) + p(B)
Given that p(A) = 2/10 and p(A ∪ B') = 3/10, we can rewrite the equation as:
2/10 + p(B) = 3/10
Subtracting 2/10 from both sides, we get:
p(B) = 3/10 - 2/10
p(B) = 1/10
Therefore, the probability of event B occurring is 1/10.
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