Find the sum of the first twelve terms of the sequence 2, 5, 8, 11?

To find the sum of the first twelve terms of the sequence 2, 5, 8, 11, we first need to find the common difference between the terms.

The common difference between each term is 3 (5 - 2 = 3, 8 - 5 = 3, 11 - 8 = 3).

To find the sum of the first twelve terms, we can use the formula for the sum of an arithmetic series:

Sn = n/2 * (2a + (n-1)d)

where:
Sn = sum of the first n terms
n = number of terms
a = first term
d = common difference

Plugging in the values:
n = 12
a = 2
d = 3

Sn = 12/2 * (2(2) + (12-1)3)
Sn = 6 * (4 + 33)
Sn = 6 * 37
Sn = 222

Therefore, the sum of the first twelve terms of the sequence 2, 5, 8, 11 is 222.