To find the oxidation number of P in H2PO4, we first need to determine the oxidation numbers of the other elements in the compound.
The oxidation number of hydrogen (H) is always +1 in compounds.
The oxidation number of oxygen (O) is typically -2 in compounds, but in this case, there are four oxygen atoms in the H2PO4 ion, giving a total oxidation number of -8.
Since the overall charge of the H2PO4 ion is -1, the oxidation number of phosphorus (P) can be calculated using the formula:
(+1 * 2) + x + (-8) = -1 2 + x - 8 = -1 x = +7
Therefore, the oxidation number of phosphorus (P) in H2PO4 is +7.