Find the logarithms and antilogarithm of 0.06295 ÷ 0.8183.

To find the logarithm of 0.06295 ÷ 0.8183, we can use the property of logarithms that states log(a ÷ b) = log(a) - log(b).

So, log(0.06295 ÷ 0.8183) = log(0.06295) - log(0.8183)

Using a calculator, we find that log(0.06295) ≈ -1.2024 and log(0.8183) ≈ -0.0877.

Therefore, log(0.06295 ÷ 0.8183) ≈ -1.2024 - (-0.0877) ≈ -1.1147.

To find the antilogarithm of -1.1147, we can use the property that states antilog(x) = 10^x.

So, antilog(-1.1147) = 10^-1.1147 ≈ 0.0837.

Therefore, the logarithm of 0.06295 ÷ 0.8183 is approximately -1.1147 and the antilogarithm of -1.1147 is approximately 0.0837.

Logarithm (log)

```
log(0.06295 ÷ 0.8183) = log(0.076953)
```

Antilogarithm (antilog)

```
antilog(0.076953) = 0.1186
```