Equation v^2=u^2+2as is in dimensionally correct?

Yes, the equation v^2=u^2+2as is dimensionally correct.

The dimensions of the variables in the equation are as follows:
- v (final velocity) has dimensions of length/time
- u (initial velocity) has dimensions of length/time
- a (acceleration) has dimensions of length/time^2
- s (displacement) has dimensions of length

Substituting these dimensions into the equation, we get:
(length/time)^2 = (length/time)^2 + 2(length/time^2)(length)

This simplifies to:
(length^2/time^2) = (length^2/time^2) + 2(length^2/time^2)

Therefore, the equation is dimensionally correct.