Calculate wavelength 1.00eV from ground level up to 3.00eV?

To calculate the wavelength of a photon with energy 1.00 eV, we can use the formula:

wavelength = hc / energy

where:
h = Planck's constant = 4.135667696 x 10^-15 eV s
c = speed of light = 3.00 x 10^8 m/s
energy = 1.00 eV = 1.602176634 x 10^-19 J

Plugging in the values:

wavelength = (4.135667696 x 10^-15 eV s * 3.00 x 10^8 m/s) / (1.602176634 x 10^-19 J)
wavelength = 7.85 x 10^-7 m

Now, to calculate the wavelength of a photon with energy 3.00 eV, we can use the same formula:

energy = 3.00 eV = 4.806529902 x 10^-19 J

Plugging in the values:

wavelength = (4.135667696 x 10^-15 eV s * 3.00 x 10^8 m/s) / (4.806529902 x 10^-19 J)
wavelength = 2.07 x 10^-7 m

Therefore, the wavelength of a photon with energy 1.00 eV is 7.85 x 10^-7 m and the wavelength of a photon with energy 3.00 eV is 2.07 x 10^-7 m.

The energy of a photon is given by:

$$E = hf = \frac{hc}{\lambda}$$

where:

- E is the energy of the photon in joules (J)
- h is Planck's constant (6.63 x 10^-34 J s)
- f is the frequency of the photon in hertz (Hz)
- c is the speed of light in vacuum (2.998 x 10^8 m/s)
- λ is the wavelength of the photon in meters (m)

We need to calculate the wavelength of a photon with an energy of 1.00 eV (electron volt). 1 eV is equal to 1.602 x 10^-19 J.

$$ \lambda = \frac{hc}{E}= \frac{6.63 \times 10^{-34} \text{ Js} \times 2.998 \times 10^8 \text{ m/s}}{1.602 \times 10^{-19} \text{ J}} = 1.239 \times 10^{-6} \text{ m} = 1239 \text{ nm} $$

Therefore, the wavelength of a photon with an energy of 1.00 eV is 1239 nm.

Now, we need to calculate the wavelength of a photon with an energy of 3.00 eV.

$$ \lambda = \frac{hc}{E}= \frac{6.63 \times 10^{-34} \text{ Js} \times 2.998 \times 10^8 \text{ m/s}}{4.806 \times 10^{-19} \text{ J}} = 413 \text{ nm} $$

Therefore, the wavelength of a photon with an energy of 3.00 eV is 413 nm.