qu
answer
Homepage
Ask!
Experts
Search
English
Notifications
Login
qu
answer
Homepage
Experts
Ask!
Notifications
Login
Loading...
>
#calculations
,
#wind-energy
,
#physics
>
Calculate upstream windpower density when velocity of 20m/s and mass densit of1.225kg/m?
Anonymous
Mar 20
Subscribe
Subscribed
Copy Link
Share
Embed
Report Question
#calculations
#wind-energy
#physics
Calculate upstream windpower density when velocity of 20m/s and mass densit of1.225kg/m?
1 view
1 view
1
answer
Sort By
Date
Score
ChatGPT
Mar 20
Report Answer
The formula to calculate wind power density is:
Wind Power Density = 0.5 * mass density * velocity^3
Given:
Velocity = 20 m/s
Mass density = 1.225 kg/m^3
Wind Power Density = 0.5 * 1.225 * 20^3
Wind Power Density = 0.5 * 1.225 * 8000
Wind Power Density = 4900 J/m^3
Therefore, the upstream wind power density is 4900 J/m^3.
0
You
Click here to log in
uploading image...
Anonymous answer
Add Answer
Similar Questions
Characteristics of concave mirrors:
Applications of insulators
What are the properties of cathode rays?
A cup is 5/13 full of milk. What part of the cup is still to be filled by milk to make it full?
Define depth of modulation as applied to a modulated wave.
Define Doppler effect.
Vectors
How is a carburetor used with Bernoulli's principle?
Write notes about demagnetization and magnetic fields?
What is the difference between linear measurement and angular measurement?
×
Please log in to continue.
×
Login with Facebook
Login with Google
Login with Twitter
By proceeding, you agree to our
Terms Of Use
and confirm you have read our
Privacy Policy
.
OR
Click here to log in
Embed
×
Width
px
Height
px
Dynamic width
Show picture
Show description
Title - visible rows
1
2
3
4
5
6
7
8
9
10
Description - visible rows
1
2
3
4
5
6
7
8
9
10
×
Sexual content
Violent or repulsive content
Hateful or abusive content
Spam or misleading
Infringes my rights
Other
Request to block the user (the user will not have permission to post on Quanswer).
Please select a reason before submitting the report.
Thank you for helping us keep the content on Quanswer as high-quality as possible. We received your feedback and we will review it shortly.
×
Anonymous
Login
Ask!
Homepage
Experts
Tags
Search
Be one of the experts
About Us
Frequently Asked Questions
Contact Us
Terms Of Use
Privacy Policy
© 2024 - Quanswer
Select language
×
Magyar
Română
Español
Kiswahili
Français
Português
Deutsch
Nederlands
Norsk