A straight line passes through points (-2,5) and (2,-3) determine the equation of the line?

To determine the equation of the line passing through the points (-2,5) and (2,-3), we first need to find the slope of the line.

The formula for finding the slope of a line passing through two points (x1, y1) and (x2, y2) is:

m = (y2 - y1) / (x2 - x1)

Using the points (-2,5) and (2,-3):

m = (-3 - 5) / (2 - (-2))
m = (-8) / 4
m = -2

Now that we have the slope, we can use the point-slope form of the equation of a line to find the equation of the line:

y - y1 = m(x - x1)

Using the point (-2,5):

y - 5 = -2(x - (-2))
y - 5 = -2(x + 2)
y - 5 = -2x - 4
y = -2x + 1

Therefore, the equation of the line passing through the points (-2,5) and (2,-3) is y = -2x + 1.