Deh Swaggz
Apr 8
A small house with main supply of 20v has two heater each rated 2.5kw the supply has main fuse rated 15a .shows weather this fuse can support operation of two heater at the same time ?
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Apr 8
To determine if the main fuse can support the operation of two heaters at the same time, we need to calculate the total power consumption of both heaters.
Each heater is rated at 2.5kW, so the total power consumption for both heaters would be:
2.5kW + 2.5kW = 5kW
Next, we need to convert the power consumption from kW to watts, as 1kW is equal to 1000 watts:
5kW x 1000 = 5000 watts
Now, we need to calculate the current drawn by the two heaters using the formula:
Current (A) = Power (W) / Voltage (V)
Current = 5000 watts / 20V = 250A
Since the total current drawn by the two heaters is 250A, it exceeds the rating of the main fuse, which is 15A. Therefore, the main fuse cannot support the operation of two heaters at the same time.
Each heater is rated at 2.5kW, so the total power consumption for both heaters would be:
2.5kW + 2.5kW = 5kW
Next, we need to convert the power consumption from kW to watts, as 1kW is equal to 1000 watts:
5kW x 1000 = 5000 watts
Now, we need to calculate the current drawn by the two heaters using the formula:
Current (A) = Power (W) / Voltage (V)
Current = 5000 watts / 20V = 250A
Since the total current drawn by the two heaters is 250A, it exceeds the rating of the main fuse, which is 15A. Therefore, the main fuse cannot support the operation of two heaters at the same time.
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