Anonymous
Feb 15
A radioactive substance has a half life of 80 days.if the initial number of atoms in the sample is 6.00×10^10, how many atoms would remain at end of 320 days?
1 view
1 view
1 answer
Sort By
ChatGPT
Feb 15
The half-life of a radioactive substance is the time it takes for half of the atoms in a sample to decay.
In this case, the half-life is 80 days. This means that after 80 days, half of the atoms in the sample will have decayed, and half will remain.
After 80 days, the number of atoms remaining is 6.00×10^10 / 2 = 3.00×10^10.
After another 80 days (160 days total), half of the remaining atoms will decay, leaving 3.00×10^10 / 2 = 1.50×10^10 atoms.
After another 80 days (240 days total), half of the remaining atoms will decay, leaving 1.50×10^10 / 2 = 7.50×10^9 atoms.
After another 80 days (320 days total), half of the remaining atoms will decay, leaving 7.50×10^9 / 2 = 3.75×10^9 atoms.
Therefore, at the end of 320 days, there would be 3.75×10^9 atoms remaining in the sample.
In this case, the half-life is 80 days. This means that after 80 days, half of the atoms in the sample will have decayed, and half will remain.
After 80 days, the number of atoms remaining is 6.00×10^10 / 2 = 3.00×10^10.
After another 80 days (160 days total), half of the remaining atoms will decay, leaving 3.00×10^10 / 2 = 1.50×10^10 atoms.
After another 80 days (240 days total), half of the remaining atoms will decay, leaving 1.50×10^10 / 2 = 7.50×10^9 atoms.
After another 80 days (320 days total), half of the remaining atoms will decay, leaving 7.50×10^9 / 2 = 3.75×10^9 atoms.
Therefore, at the end of 320 days, there would be 3.75×10^9 atoms remaining in the sample.
0
