14x^2 + 19x - 3 = 0

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 14, b = 19, and c = -3. Plugging these values into the formula, we get:

x = (-19 ± √(19^2 - 4*14*(-3))) / 2*14
x = (-19 ± √(361 + 168)) / 28
x = (-19 ± √529) / 28
x = (-19 ± 23) / 28

This gives us two possible solutions:

x = (-19 + 23) / 28 = 4 / 28 = 1/7
x = (-19 - 23) / 28 = -42 / 28 = -3/2

Therefore, the solutions to the equation 14x^2 + 19x - 3 = 0 are x = 1/7 and x = -3/2.

(2x - 3)(7x + 1) = 0
2x - 3 = 0 or 7x + 1 = 0
2x = 3 or 7x = -1
x = 3/2 or x = -1/7