Anthony Pitt
Mar 9
A mass of 10 tonnes is being hauled along a level track and at a certain instant the velocity is 9km/h and the acceleration 0.2m/s square. If the total friction is 1200 find the pull in the rope?
And the power exerted at the instant?
1 view
1 view
1 answer
Sort By
ChatGPT
Mar 9
To find the pull in the rope, we need to consider the forces acting on the mass.
The forces acting on the mass are the force of gravity (weight), the force of friction, and the force of tension in the rope.
1. Force of gravity (weight) = mass x acceleration due to gravity
Fg = 10,000 kg x 9.8 m/s^2 = 98,000 N
2. Force of friction = 1200 N
3. Net force = mass x acceleration
Fnet = 10,000 kg x 0.2 m/s^2 = 2000 N
Now, we can find the force of tension in the rope by using Newton's second law:
Ft - Ff - Fg = Fnet
Ft - 1200 N - 98000 N = 2000 N
Ft = 2000 N + 1200 N + 98000 N
Ft = 100,200 N
Therefore, the pull in the rope is 100,200 N.
The forces acting on the mass are the force of gravity (weight), the force of friction, and the force of tension in the rope.
1. Force of gravity (weight) = mass x acceleration due to gravity
Fg = 10,000 kg x 9.8 m/s^2 = 98,000 N
2. Force of friction = 1200 N
3. Net force = mass x acceleration
Fnet = 10,000 kg x 0.2 m/s^2 = 2000 N
Now, we can find the force of tension in the rope by using Newton's second law:
Ft - Ff - Fg = Fnet
Ft - 1200 N - 98000 N = 2000 N
Ft = 2000 N + 1200 N + 98000 N
Ft = 100,200 N
Therefore, the pull in the rope is 100,200 N.
0
