Anonymous
Mar 21
A man walks 1 km due east and then 1 km due north his displacement is ??
Physics
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Mar 21
The man's displacement can be calculated using the Pythagorean theorem, as he has moved both east and north.
The distance he walked east is 1 km, and the distance he walked north is also 1 km.
Using the Pythagorean theorem:
Displacement = √(1^2 + 1^2)
Displacement = √(1 + 1)
Displacement = √2
Therefore, the man's displacement is √2 km.
The distance he walked east is 1 km, and the distance he walked north is also 1 km.
Using the Pythagorean theorem:
Displacement = √(1^2 + 1^2)
Displacement = √(1 + 1)
Displacement = √2
Therefore, the man's displacement is √2 km.
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