A laser emits light that has a frequency of 4.69*10 the power of 14 second inverse. What the energy of one photon of this radiation? ?

To calculate the energy of one photon of this radiation, we can use the formula:

E = hf

Where:
E = energy of the photon
h = Planck's constant (6.626 x 10^-34 J*s)
f = frequency of the radiation (4.69 x 10^14 s^-1)

Plugging in the values:

E = (6.626 x 10^-34 J*s) * (4.69 x 10^14 s^-1)
E = 3.11 x 10^-19 Joules

Therefore, the energy of one photon of this radiation is 3.11 x 10^-19 Joules.

The energy of a photon is given by the equation:

E = hf

where:

E is the energy of the photon in joules (J)
h is Planck's constant (6.63-10-34 J s)
f is the frequency of the radiation in hertz (Hz)

In this problem, the frequency of the radiation is 4.69-10^14 Hz. Substituting this value into the equation above, we get:

E = (6.63-10-34 J s)(4.69-10^14 Hz)
E = 2.99-10-19 J

Therefore, the energy of one photon of this radiation is 2.99-10-19 J.