A choke coil of negligible is to limit the current through it to 50mA when 25Vis applied across it at 400kHz. Find it's inductance, find inductance reactance by Ohm's law and then find inductance?

To find the inductance of the choke coil, we can use the formula:

Inductive reactance (XL) = 2πfL

Where:
XL = Inductive reactance
f = Frequency
L = Inductance

Given:
Current (I) = 50mA = 0.05A
Voltage (V) = 25V
Frequency (f) = 400kHz = 400,000Hz

First, let's find the inductive reactance (XL) using Ohm's law:

XL = V / I
XL = 25V / 0.05A
XL = 500Ω

Now, let's find the inductance (L) using the formula:

XL = 2πfL
500Ω = 2π(400,000Hz)L

Rearranging the formula to solve for L:

L = XL / (2πf)
L = 500Ω / (2π * 400,000Hz)
L ≈ 0.198 mH

Therefore, the inductance of the choke coil is approximately 0.198 mH.