[2 3 6 4 5 7 1 5 3 ] solve det?

To find the determinant of a 3x3 matrix, you can use the following formula:

det(A) = a(ei − fh) − b(di − fg) + c(dh − eg)

Given the matrix:

[2 3 6
4 5 7
1 5 3]

We can plug in the values for a, b, c, d, e, f, g, and h:

a = 2, b = 3, c = 6
d = 4, e = 5, f = 7
g = 1, h = 5

Now we can calculate the determinant:

det(A) = 2(5*3 - 7*5) - 3(4*3 - 7*1) + 6(4*5 - 5*1)
det(A) = 2(15 - 35) - 3(12 - 7) + 6(20 - 5)
det(A) = 2(-20) - 3(5) + 6(15)
det(A) = -40 - 15 + 90
det(A) = 35

Therefore, the determinant of the given 3x3 matrix is 35.