x² + 1/x² = 18. Then what is the value of x - 1/x?
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more than 3 weeks ago
Let's first simplify the given equation x² + 1/x² = 18.
Multiplying through by x², we get: x^4 + 1 = 18x²
Rearranging terms, we get: x^4 - 18x² + 1 = 0
Let y = x², then the equation becomes: y² - 18y + 1 = 0
Solving this quadratic equation for y using the quadratic formula: y = (18 ± √(18² - 4*1*1)) / 2 y = (18 ± √(324 - 4)) / 2 y = (18 ± √320) / 2 y = (18 ± 4√5) / 2
y = 9 ± 2√5
Since y = x², we have two possible values for x: x = √(9 + 2√5) or x = √(9 - 2√5)
Now, let's find the value of x - 1/x for each case:
For x = √(9 + 2√5): x - 1/x = √(9 + 2√5) - 1/√(9 + 2√5) x - 1/x = √(9 + 2√5) - √(9 - 2√5) x - 1/x = √(9 + 2√5) - √(9 - 2√5)
For x = √(9 - 2√5): x - 1/x = √(9 - 2√5) - 1/√(9 - 2√5) x - 1/x = √(9 - 2√5) - √(9 + 2√5) x - 1/x = √(9 - 2√5) - √(9 + 2√5)
Therefore, the value of x - 1/x can be either √(9 + 2√5) - √(9 - 2√5) or √(9 - 2√5) - √(9 + 2√5), depending on the value of x.