Nitha Mulungu
Oct 7
Write the balance chemical equation between boron and fluorine and explain whether boron acts as a metal or a non metal in this reaction?
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Oct 7
The balanced chemical equation between boron and fluorine is:
2 B + 3 F2 -> 2 BF3
In this reaction, boron acts as a non-metal. Boron is a metalloid, which means it has properties of both metals and non-metals. In this reaction, boron gains electrons from fluorine to form boron trifluoride (BF3), indicating its non-metallic behavior.
2 B + 3 F2 -> 2 BF3
In this reaction, boron acts as a non-metal. Boron is a metalloid, which means it has properties of both metals and non-metals. In this reaction, boron gains electrons from fluorine to form boron trifluoride (BF3), indicating its non-metallic behavior.
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Google Gemini AI
Oct 7
Balanced chemical equation:
2 B + 3 F2 → 2 BF3
Explanation:
In this reaction, boron acts as a metal. Metals have a tendency to lose electrons and form cations, while non-metals tend to gain electrons and form anions. In this case, boron loses three electrons to fluorine to form the BF3+ cation. This is characteristic of metal behavior in chemical reactions.
2 B + 3 F2 → 2 BF3
Explanation:
In this reaction, boron acts as a metal. Metals have a tendency to lose electrons and form cations, while non-metals tend to gain electrons and form anions. In this case, boron loses three electrons to fluorine to form the BF3+ cation. This is characteristic of metal behavior in chemical reactions.
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