What quantity of heat will be necessary to change 2kg of ice at 0c⁰ to water at 10c⁰ specific latent heat of fusion of ice =3.36*10⁵jkg-¹k-¹ at specific heat capacity of water 4200jkg-¹k-¹??

To calculate the quantity of heat required to change 2kg of ice at 0°C to water at 10°C, we need to consider two processes:

1. Heating the ice from 0°C to 0°C water:
Q1 = mcΔT
Q1 = 2kg * 2100J/kg°C * (0°C - 0°C)
Q1 = 0J

2. Melting the ice into water at 0°C:
Q2 = mL
Q2 = 2kg * 3.36*10^5J/kg * 1kg
Q2 = 6.72*10^5J

3. Heating the water from 0°C to 10°C:
Q3 = mcΔT
Q3 = 2kg * 4200J/kg°C * (10°C - 0°C)
Q3 = 84,000J

Therefore, the total quantity of heat required is:
Q = Q1 + Q2 + Q3
Q = 0J + 6.72*10^5J + 84,000J
Q = 7.02*10^5J

Therefore, 7.02*10^5J of heat will be necessary to change 2kg of ice at 0°C to water at 10°C.