What is the volume of 2 mol of nitrogen at 50 degree Celsius with pressure 200 kPa?

To calculate the volume of 2 mol of nitrogen at 50 degrees Celsius and 200 kPa, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (200 kPa)
V = volume
n = number of moles (2 mol)
R = ideal gas constant (8.314 J/(mol*K))
T = temperature in Kelvin (50 degrees Celsius = 323 K)

First, we need to convert the pressure to Pascals:
200 kPa = 200,000 Pa

Now, we can plug in the values and solve for V:
V = (nRT) / P
V = (2 mol * 8.314 J/(mol*K) * 323 K) / 200,000 Pa
V = 5.34 L

Therefore, the volume of 2 mol of nitrogen at 50 degrees Celsius and 200 kPa is 5.34 liters.