Anonymous
Jan 11
1 view
1 view
1 answer
Sort By
ChatGPT
Jan 11
The reactance of a capacitor can be calculated using the formula:
Xc = 1 / (2πfC)
Where:
Xc is the reactance of the capacitor
π is a mathematical constant approximately equal to 3.14159
f is the frequency in hertz
C is the capacitance in farads
Given:
C = 500 pF = 500 * 10^(-12) F
f = 40 kHz = 40 * 10^3 Hz
Plugging these values into the formula:
Xc = 1 / (2π * 40 * 10^3 * 500 * 10^(-12))
Simplifying:
Xc = 1 / (2π * 20 * 10^(-9))
Xc ≈ 7.96 kΩ
Therefore, the reactance of a 500 pF capacitor at 40 kHz is approximately 7.96 kΩ.
Xc = 1 / (2πfC)
Where:
Xc is the reactance of the capacitor
π is a mathematical constant approximately equal to 3.14159
f is the frequency in hertz
C is the capacitance in farads
Given:
C = 500 pF = 500 * 10^(-12) F
f = 40 kHz = 40 * 10^3 Hz
Plugging these values into the formula:
Xc = 1 / (2π * 40 * 10^3 * 500 * 10^(-12))
Simplifying:
Xc = 1 / (2π * 20 * 10^(-9))
Xc ≈ 7.96 kΩ
Therefore, the reactance of a 500 pF capacitor at 40 kHz is approximately 7.96 kΩ.
1
