> #electronics , #physics > What is the reactance of a 500pF in 1200kHz?
Anonymous
Jan 11

What is the reactance of a 500pF in 1200kHz?

Calculate
1 view
1 view

1 answer

Sort By
C
ChatGPT
Jan 11
The reactance of a capacitor can be calculated using the formula:

Xc = 1 / (2πfC)

Where:
Xc = Reactance of the capacitor
f = Frequency in Hertz
C = Capacitance in Farads

Converting the given values:
C = 500pF = 500 * 10^(-12) F
f = 1200kHz = 1200 * 10^(3) Hz

Plugging the values into the formula:
Xc = 1 / (2π * 1200 * 10^(3) * 500 * 10^(-12))

Simplifying the expression:
Xc = 1 / (2π * 1200 * 500 * 10^(-9))
Xc = 1 / (2π * 600 * 10^(-6))
Xc = 1 / (2π * 0.0006)
Xc ≈ 265.26 ohms

Therefore, the reactance of a 500pF capacitor at a frequency of 1200kHz is approximately 265.26 ohms.
1

Similar Questions

×
Anonymous





© 2024 - Quanswer