What is the density of NH3(g) kept at 800 mmHg and 50 °C?

To find the density of NH3(g) at 800 mmHg and 50 °C, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (800 mmHg)
V = volume (we can assume 1 L for simplicity)
n = number of moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin (50 °C = 323 K)

First, we need to calculate the number of moles of NH3 using the ideal gas law equation:

n = (PV) / (RT)
n = (800 mmHg * 1 L) / (0.0821 L.atm/mol.K * 323 K)
n = 24.8 moles

Next, we need to calculate the molar mass of NH3:

NH3 = 1(N) + 3(H) = 14.01 g/mol + 3(1.01 g/mol) = 17.03 g/mol

Now, we can calculate the density of NH3:

Density = (mass) / (volume)
Density = (24.8 moles * 17.03 g/mol) / 1 L
Density = 422.94 g/L

Therefore, the density of NH3(g) at 800 mmHg and 50 °C is 422.94 g/L.

Given:

- Pressure (P) = 800 mmHg
- Temperature (T) = 50 °C = 323 K

Calculate the density (ρ):

Step 1: Convert pressure to Pa:

1 mmHg = 133.322 Pa

P (Pa) = 800 mmHg x 133.322 Pa/mmHg = 106655.76 Pa

Step 2: Use the Ideal Gas Law to calculate the number of moles (n):

PV = nRT

n = PV/RT = (106655.76 Pa x 1 L) / (8.314 J/mol K x 323 K) = 4.106 mol

Step 3: Calculate the volume (V):

V = 1 L

Step 4: Calculate the mass (m) of NH3:

Molar mass of NH3 = 14 + 3 x 1 = 17 g/mol

m = n x M = 4.106 mol x 17 g/mol = 69.79 g

Step 5: Calculate the density:

ρ = m/V = 69.79 g / 1 L = 0.0698 g/L

Therefore, the density of NH3(g) at 800 mmHg and 50 °C is 0.0698 g/L.