What is the compound interest earned on R50,000 that is invested for 12 years at 8% per annum?

The formula for compound interest is:

A = P(1 + r/n)^(nt)

Where:
A = the future value of the investment/loan, including interest
P = the principal investment amount (R50,000)
r = the annual interest rate (8% or 0.08)
n = the number of times that interest is compounded per year (assuming it is compounded annually, n = 1)
t = the number of years the money is invested for (12 years)

Plugging in the values:

A = R50,000(1 + 0.08/1)^(1*12)
A = R50,000(1.08)^12
A = R50,000(2.937901)
A = R146,895.05

The compound interest earned on the investment is R146,895.05 - R50,000 = R96,895.05.

The formula for compound interest is:

A = P(1 + r/n)^(nt)

Where:
- A is the final amount
- P is the principal (initial investment)
- r is the annual interest rate (as a decimal)
- n is the number of times the interest is compounded per year
- t is the number of years

In this case, we have:
- P = R50,000
- r = 8% (or 0.08)
- n = 1 (since the interest is compounded annually)
- t = 12

Plugging these values into the formula, we get:

A = 50,000(1 + 0.08/1)^(1-12)
A = 50,000(1.08)^12
A = 50,000(2.1589)
A = R107,945

Therefore, the compound interest earned is:

A - P = 107,945 - 50,000
= R57,945